0:00
Hello everybody.
00:01
Here in this problem, let the submerged part of the solid or the ice is small v.
00:07
So here in a container, say some liquid is there and here the ice is submerged by a volume that is small v and the total volume is capital v.
00:20
So we can say weight of displaced liquid is equal to small v rho l, rho l is the density of the liquid, into g and the apparent weight of the solid here is the ice, so capital v, rho s, rho s is the density of the solid, into g.
00:59
So we see that by the concept v rho s should be equal to small v rho l or small v by capital v should be equal to rho s by rho l and here it is given as 91 .7 by 100 that is 0 .917.
01:29
Now in the first part, v we see is capital v into rho s by rho l, rho s by rho l value we know that is 917 .917.
01:44
So it will become 1 meter cube into 0 .917.
01:50
So it will be 0 .917 that much meter cube.
01:55
So submerged part will have a volume that is 0 .917 meter cube.
01:59
Now in part b of the problem, mass of water, mass of water that is equal to small m and that is equal to volume into density that is rho l and that will be equal to and this volume is simply small v...