00:01
Hello students, in this question it is given that the benzyl on reaction with dibenzyl ketone gives tetraphenylcyclopentadienone.
00:09
This tetraphenylcyclopentadienone reacts with two equivalent moles of diphenylacetylene to give hexaphenylbenzene.
00:19
We have to find out the theoretical yield of hexaphenylbenzene.
00:24
For that we have to find out the limiting reagent among these two reactants.
00:30
For that we have to know the number of moles of tetraphenylcyclopentane which can be calculated from the first equation.
00:37
First of all we are going to find out the limiting reagent from these two reactants which is can be calculated using the formula n is equal to mass divided by molar mass.
00:50
Substituting the value number of moles of benzene will be given by mass 2 gram divided by molar mass 210 .23.
01:01
On solving this we will get 0 .0095 moles.
01:07
Similarly the number of moles of dibenzyl ketone is given by 2 divided by molar mass which is equal to 210 .28.
01:19
This is also equal to 0 .0095 mole.
01:25
Hence these two can acts as a limiting reagent.
01:29
Let us consider benzyl as the limiting reagent for this case...