To do this, we need to make sure that the probability density function (pdf) integrates to 1 over the given interval (0 < x < 2). So, we have:
$$\int_0^2 K(4x - 2x^2) dx = 1$$
Now, let's integrate the function:
$$K \int_0^2 (4x - 2x^2) dx = K \left[ 2x^2 -
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