An electron is placed in an electric field of intensity 1000 N/C. Calculate the force acting on an electron. (charge on electron=1.6 x 10^-19 C) 1.6 x 10^-19 N 1.6 x 10^-22 N 1.6 x 10^-16 N 0.625 x 10^22 N
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The electric field intensity \( E \) is given as 1000 N/C, and the charge of an electron \( q \) is \( 1.6 \times 10^{-19} \) C. Show more…
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