The peak current required to radiate a power of 50 W at 50 MHz from a 0.01 m Hertzian dipole is ______ A. (Rounded off to two decimal places)
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01 m Hertzian dipole, we need to use the formula for the power radiated by a small dipole antenna. The power radiated by a Hertzian dipole is given by: \[ P = \frac{80 \pi^2}{3} \left( \frac{I_0 l}{\lambda} \right)^2 \] where: - \( P \) is the radiated power, - Show more…
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