1 increase in speed. Since it's a compound reverted gear train, we can represent the gear ratios as:
$R = \frac{N_1}{N_2} \cdot \frac{N_3}{N_4}$
Where $R$ is the overall gear ratio, and $N_1, N_2, N_3, N_4$ are the teeth numbers of the gears.
For an exact 56.1
Show more…