00:03
In the given question, we need to convert the given cartesian equation into polar equation.
00:08
Now, if we check this cartesian coordinate system, and this is your x axis, and this is a y -axis, and we take a point, x, comma, y, which is at a distance of r from the origin and at an angle of theta.
00:22
Now, if you drop a perpendicular to the axis, then this distance will be x, and if a perpendicular to the y -axis, then this distance will be y.
00:33
Now if you consider this triangle, this o, a, b, let this be c.
00:40
Then in that triangle oa, b, we can see that x by r, which is based by hypertenuous, so that will be cos of angle theta...