The following frequency table of data represents the number of employee turnovers per month for an ad agency, what is the potential outlier? Value Frequency 16 3 17 5 18 6 19 8 20 4 21 4 22 0 23 0 24 0 25 0 26 0 27 0 28 0 29 1 Select the correct answer below:
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To do this, we can use the following formulas: Mean: $\mu = \frac{\sum{xf}}{n}$ Standard Deviation: $\sigma = \sqrt{\frac{\sum{(x - \mu)^2f}}{n}}$ Where $x$ is the value, $f$ is the frequency, and $n$ is the total number of data points. Show more…
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