00:01
The question is asking to find the acceleration of the object as it slashed down the ramp and also it is asking to find the velocity at the end of the ramp.
00:08
Let us hide the given data.
00:11
Given the angle of communication theta is equal to 30 degree and the distance it need to be slided is equal to 1 meter in the coefficient of static and kinetic friction.
00:21
Nu yes can mu k is equal to 0 .5 here the body is sliding so we will concept only mu k and let us draw the diagram.
00:32
Let m be the mass of the body and on taking the result and we get mg cost, mg sinita and the mg kata around the x incline and y gain and axis.
00:41
And data is the angle 30 degree.
00:43
So we need to find friction force acting in the direction of x inclined.
00:47
So we get we know f is equal to mu, here n is the normal first and mu can be taken as f, mu k, why because it is sliding and is a normal verse of the body.
00:59
Here along y inclined axis, the forces acting out n is equal to only m g cost theta.
01:10
So we shall substitute this in this equation we get f is equal to mu k m g cross theta...