00:01
So we are given that for 8085 sorry 8086 microprocessor the total memory should be of 128 kilobytes.
00:17
By using a ram chip of size 16 kb we have to provide the interface for an 8086 microprocessor.
00:29
So let us start with the concept which we are going to use here for this question.
00:36
So first of all we need to know the number of chips required.
00:42
So what kind of chip that is ram random accessory memory chip required.
00:50
So this should be equals to we want to make it for 128 of kb by the means of 16 kb ram chip.
00:59
So we just need to divide 128 kb by 16 kb.
01:03
So this should become equals to 128 kb can be written as 2 to the power second 7 of kbs by 16 can be written as 2 to the power 4 kb.
01:16
So 7 minus 4 will become 3 that means it will be 2 to the power 3 which will be goes to 8.
01:26
So we required 8 ram chips here.
01:31
Hence therefore according to this let's suppose this is nothing but what the microprocessor 8086 in which we have to fix 8 chips...