00:01
Hello, here we have to find the current which flows through the resistance r4.
00:08
To better solve it, let's first redraw this circuit.
00:15
So r1 is connected in cv to r2, and in turn it's also connected, r2 is in parallel to r5.
00:36
And also r2 is in civ to r3, which is in parallel to r4.
00:51
And this is all connected to the emf.
00:57
So we have to first calculate the resistance of the circuit r1, 2, 3, 4, 5.
01:04
So that equals to r1 plus r2, 3, 4, 5.
01:11
R2 -34 -5 equals to r5 times r2 -3 -4 over r2 -3 -4 plus r5 and r2 -3 -4 equals to r2 plus r3 -4 and r2 -4 equals to r3 -4 and r4, sorry, r3 -4 equals to r3.
01:51
Times r4 over r3 plus r4.
01:56
So let's start calculating r3 and is 9 oms.
02:03
So it's multiplied by 6 oms.
02:07
And that's divided by the sum of these two resistances.
02:14
Let's calculate it.
02:27
That equals to 3 .60 oms.
02:30
So then let's calculate r234, that is r2, that is 3 oms.
02:42
Plus r34, which is 3 .60 oms.
02:50
So that equals to 6 .60 oms.
02:59
R2345 equals to r234, which is 6 .60 oms times r5, that is 11 oms.
03:18
And that's divided by 11 oms plus 6 .60 oms.
03:23
That equals to 4 .125 oms.
03:43
So let's see if this number is this and we will run later.
03:47
So the overall resistance equals to r1, which is 12 oms, plus 4 .125 oms...