00:01
Let's discuss this question.
00:02
So here we have two disc a and b, each with mass 1 kilograms, an initial velocity shown before they collide.
00:09
So we need to determine their speed just after the impact.
00:13
So here we can say v -a -1 is equal to 4 meter per second and here ma, that is equal to m -b, that is mass is given as 1 kilograms for both of them.
00:29
So along line of impact, 10 theta is equal to 4 divided by 3, sine theta is equal to 4 divided by 5 and cos theta is equal to 3 divided by 5.
00:53
So here we can say e is equal to v vector b2 minus v vector a2.
01:03
This is x this is divided by v vector a1 x minus v vector b1 x so here we can say 0 .5 is equal to v b2x minus v a2x divided by minus v a1 sine theta minus v b b1 plus theta so here we can say 0 .5 is equal to vb2x minus v .a1 x divided by minus of 4 multiplied by 4 divided by 5 plus 3 multiplied by 3 divided by 5.
01:49
So here we can say v .a1 x minus v b2 x that is equal to 2 .5 and this is equation number 1...