Question 3. Synthesis (12 points). A) Propose a synthetic...

Question 3. Synthesis (12 points). A) Propose a synthetic route to perform the following transformation. Give reagents for each step in the following transformations and draw all isolatable intermediates. You may use any inorganic reagents necessary. B) Propose a synthetic route to form the following compound. All carbons must come from acetylene (HC?CH). Give reagents for each step in the following transformations and draw all isolatable intermediates. You may use any inorganic reagents necessary. Question 4. Mechanisms (16 points). A) Draw a stepwise mechanism for the reaction of 2-methylbutane. Use curved arrows to show electron movement, and include all reactive intermediates and resonance structures. Show initiation and propagation steps, but you do not need to show a termination step. B) Draw a step-wise mechanism for the following reaction. Use curved arrows to show electron movement, and include all reactive intermediates and resonance structures.

Transcript

00:01 In this question they have was that synthetic root.

00:05 So here we have to perform the proposed the synthetic root for the transformation.

00:12 That is for the following transformation.

00:15 That is the they have given the cyclopentane.

00:19 So the cyclopentane it is converted to the cyclopentane 1 -2 -dial.

00:27 So for this transformations we have to propose the.

00:32 Synthetic mechanism or synthetic root and also here we have to give all the reagents in the particular transformations so here cyclopentane upon treatment with that of chlorine so here the cyclopentane it is treated with the chlorine gas so this chlorine gas in the presence of the radiation is split into the chlorine radicals chlorine radicals.

01:08 So this chlorine radicals abstracts any proton.

01:13 So for example here the proton that is present it abstracts the proton from cyclopentine and it forms cyclopental so here what happens in the cyclopentine this particular chlorine radical it abstracts the proton and it forms and it forms cyclo pentile radical, cyclopentile radical, cyclopentile radical, and h .c .l.

01:48 So the remaining one, one c .l.

01:51 Radical and cyclopentile radical.

01:55 So, and cyclopentile radical, they both react to form a chlorocyclopentine.

02:07 So they both react together to form chlorocychlorophyclopentine.

02:12 Cyclopentane.

02:14 So this chloropsyclopentane.

02:16 So here upon treatment with the top, this upon treatment with that of k -o -h in the presence of ethanol, it gives rise to ethanol, it gives rise to here.

02:30 H .l.

02:31 Will be eliminated and it gives rise to cyclopentine.

02:36 This cyclopentine upon treatment with the top, km and o4, upon treatment with km and o4 that is cold alkaline solution of the km and o4 it leads to the formation of cisdial so these are the different transformations so whenever we see the structure so here cyclopentane it is converted into chlorocyclopentine upon treatment with k -o -h ethanol it gives rise to cyclopentine upon treatment with km and o4 n -a -o -h it gives rise to cyclopentine upon treatment with kmn -o -4 n -h it gives rise to cyclopens pentane 1 to diode.

03:16 Then coming to the next one, next is transformation synthetic root.

03:21 Here, the particular ethine is converted into 2 or 3 s -3 di -bromobutane...

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