Question Two coils are adjacent when the current intensity changes in one of them from 4A to zero induced emf of 40 V is generated in the second coil and the mutual induction between the two coil 0.1 H . What is the time of the change of current? (A) 0.01 sec (B) 0.02 sec (C) 0.03 sec (D) 0.04 sec
Added by Darnell C.
Close
Step 1
- Initial current, \( I_i = 4 \, \text{A} \) - Final current, \( I_f = 0 \, \text{A} \) - Induced emf, \( \varepsilon = 40 \, \text{V} \) - Mutual inductance, \( M = 0.1 \, \text{H} \) Show more…
Show all steps
Your feedback will help us improve your experience
Monisha Shukla and 101 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
When the current changes from $+2 \mathrm{~A}$ to $-2 \mathrm{~A}$ in $0.05 \mathrm{~s}$, an emf of $8 \mathrm{~V}$ is induced in a coil. The coefficient of self-induction of the coil is : (a) $0.1 \mathrm{H}$ (b) $0.2 \mathrm{H}$ (c) $0.4 \mathrm{H}$ (d) $0.8 \mathrm{H}$
In a coil when current changes from $10 \mathrm{~A}$ to $2 \mathrm{~A}$ in time $0.1 \mathrm{~s}$, induced EMF is $3.20 \mathrm{~V}$. The self-inductance of coil is (A) $4 \mathrm{H}$ (B) $0.4 \mathrm{H}$ (C) $0.04 \mathrm{H}$ (D) $5 \mathrm{H}$
Imagine that we had two coils placed near each other. We measured an induced emf in coil 2 = 12.5 V when the current in coil 1 was changing as 0.25 A for 2 seconds. What if instead, we made the current in the other coil (coil 2) change at a constant rate of 1.2 A/s? Then what would the induced emf in coil 1 be? Assume that both coils only have 1 turn each. HINT: Remember that they will have the SAME mutual inductance!!!!
Adi S.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Watch the video solution with this free unlock.
EMAIL
PASSWORD