Question

Question 1 You throw a 2.5 kg box with a speed of 10 m/s at an angle that is 30°with the ground. How high does the box go? Group of answer choices 5.1 m 18 m 1.3 m 10 m Question 2 A bullet is fired at some angle from the horizontal on the edge of a 20 m high cliff as shown in the figure, with initial velocity components are 440 m/s (horizontal) and 86 m/s (vertical). The projectile reaches maximum height at point P and then falls and impacts the ground at point Q. What is the vertical distance between P and Q? Neglect air resistance. Group of answer choices 90,000 m 45,000 m 940 m 470 m 400 m Question 3 A car goes up a ramp with a speed of 8.0 m/s. If the horizontal component of the car's velocity vector is 4.0 m/s what must the vertical component of the car's velocity be? Group of answer choices 4.3 m/s 4.0 m/s 6.9 m/s 3.8 m/s

          Question 1
You throw a 2.5 kg box with a speed of 10 m/s at an angle that is 30°with the ground. How high does the box go?
Group of answer choices
5.1 m
18 m
1.3 m
10 m

Question 2
A bullet is fired at some angle from the horizontal on the edge of a 20 m high cliff as shown in the figure, with initial velocity components are 440 m/s (horizontal) and 86 m/s (vertical). The projectile reaches maximum height at point P and then falls and impacts the ground at point Q. What is the vertical distance between P and Q? Neglect air resistance.
Group of answer choices
90,000 m
45,000 m
940 m
470 m
400 m

Question 3
A car goes up a ramp with a speed of 8.0 m/s. If the horizontal component of the car's velocity vector is 4.0 m/s what must the vertical component of the car's velocity be?
Group of answer choices
4.3 m/s
4.0 m/s
6.9 m/s
3.8 m/s

Show more…

Question 1
You throw a 2.5 kg box with a speed of 10 m/s at an angle that is 30°with the ground. How high does the box go?
Group of answer choices
5.1 m
18 m
1.3 m
10 m

Question 2
A bullet is fired at some angle from the horizontal on the edge of a 20 m high cliff as shown in the figure, with initial velocity components are 440 m/s (horizontal) and 86 m/s (vertical). The projectile reaches maximum height at point P and then falls and impacts the ground at point Q. What is the vertical distance between P and Q? Neglect air resistance.
Group of answer choices
90,000 m
45,000 m
940 m
470 m
400 m

Question 3
A car goes up a ramp with a speed of 8.0 m/s. If the horizontal component of the car's velocity vector is 4.0 m/s what must the vertical component of the car's velocity be?
Group of answer choices
4.3 m/s
4.0 m/s
6.9 m/s
3.8 m/s

Added by Katelyn M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Christian Dell

06/08/2022

Step 1

Step 1: For the first question, we need to find the maximum height the box reaches when thrown at an angle of 30 degrees with a speed of 10 m/s. Show more…

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Question 1 You throw a 2.5 kg box with a speed of 10 m/s at an angle that is 30°with the ground. How high does the box go? Group of answer choices 5.1 m 18 m 1.3 m 10 m Question 2 A bullet is fired at some angle from the horizontal on the edge of a 20 m high cliff as shown in the figure, with initial velocity components are 440 m/s (horizontal) and 86 m/s (vertical). The projectile reaches maximum height at point P and then falls and impacts the ground at point Q. What is the vertical distance between P and Q? Neglect air resistance. Group of answer choices 90,000 m 45,000 m 940 m 470 m 400 m Question 3 A car goes up a ramp with a speed of 8.0 m/s. If the horizontal component of the car's velocity vector is 4.0 m/s what must the vertical component of the car's velocity be? Group of answer choices 4.3 m/s 4.0 m/s 6.9 m/s 3.8 m/s

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Transcript

00:01 Okay, so we have a 2 .5 kilogram box which is throwing up an angle of 30 degrees to the horizontal with a speed of 10 meters per second.

00:09 And we want to find the maximum heights.

00:11 Now, given that maximum height is how far it moves vertically upwards, we want the vertical component of this velocity.

00:17 That's going to be 10 sine 30.

00:22 It's going to have a vertical component velocity of 10 sine 30 meters per second.

00:26 We're going to use a suvat equation.

00:28 Suvat because the variable spell out suvat.

00:31 S is distance that's going to be the height that's what we want to find out u is initial velocity that's going to be 10 sign 30 at the top of its motion the highest point its vertical velocity is going to be zero it's just falls back down again so v is going to be zero and acceleration is minus 9 .81 it's minus because it's in the opposite direction to the velocity so we have v squared is equal to u squared plus 2 as so v squared minus u squared over 2a is equal to s so we have v squared is going to be equal to zero because v is equal to 0 so we have minus 10 sine 30 squared over minus 2 times 9 .81 it's going to give you s that's going to give you 1 .27 or 1 .3 meters which is your third option there then for question 2 we have a bullet fired upwards the vertical component is again is all that matters here.

01:31 The vertical component is 86 meters per second.

01:34 So we're going to find out the height that it gains from the cliff and then add on the 20 meters.

01:39 That's going to give you the vertical distance between p and q.

01:43 So again, another suvat equation.

01:45 We have u is equal to 86.

01:48 We have v is equal to zero.

01:50 Again, it's vertical velocity.

01:51 It moves upwards.

01:52 It's going to stop right at the top.

01:54 So it's vertical velocity...

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