Question 17 An inductor has a current $I(t) = I_0sin[\omega t]$ flowing through it. If the maximum emf across the inductor is equal to 0.500 V, what is the self-inductance of the inductor in mH if... $I_0 = 0.389$ A and $\omega = 257 \frac{rad}{s}$? ($1 mH = 10^{-3} H$). Round your answer to 2 decimal places.
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Step 1: The maximum emf across the inductor is given by the equation: \(\varepsilon_{max} = L \frac{dI}{dt}\) where L is the self-inductance of the inductor. Show more…
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