Consider the following table of normalized attributes of...

Consider the following table of normalized attributes of customers. Calculate the Age coordinate of Cluster 1 centroid. Write your answer to the nearest 4 decimal places. Record Age Income Cluster 1 0.24 -0.69 1 2 -0.34 0.38 1 3 0.46 -0.77 1 4 -1.59 -0.45 1 5 0.9 2.12 2 6 0.9 1.04 2 7 -1.66 -1.42 2 8 0.97 -0.06 2 9 -0.56 -0.03 2 10 0.68 -0.12 2

Transcript

00:01 Hello students, we are given a data set of age.

00:04 Age value data set is given, right? so it's a long data set.

00:07 You can see in the question.

00:08 Now we need to smooth this data by binning.

00:10 So that is the first part a bin.

00:12 So how is it binning? so bin means you have to you can use the bin depth to bin this three consecutive terms.

00:22 Ok, with the bin depth of three, you can just combine these terms so you can take the average of the first term.

00:27 So 13 13 plus 15 plus 16 divided by 3.

00:32 So first three terms by three.

00:33 So that is 14 .67 and the next term.

00:36 Similarly, you do it.

00:37 So you'll get 18 .33.

00:38 So next you'll get 20 .33.

00:41 Next three terms you'll get 23.

00:43 Next three terms 25.

00:44 Next three times 29 .33.

00:47 Next three terms 34 .33.

00:51 Next three terms 35.

00:53 Next three terms 40 .33.

00:55 Next you get 56.

00:57 So this is how you bin the data.

00:59 Now you got the bin boundaries, right? what is the bin boundary? so bin boundaries are the initial value, right? and you have the second values, right? so this is from 13 first bin boundaries from 13 to 19, 19 to 22.

01:14 So these are midpoints of these things.

01:17 19 to 22, then 22 to 30, 22 to 25, then 25 to 30.

01:22 So in between points are taken as midpoint 22 to 25, 25 to 30, 30 to 35, 35 to 40, 40 to 46, 46 to 52, 52 to 70.

01:38 Now coming to this b part, b part, now you need to use min max normalization to transform the value of 35 onto a range.

01:49 So to use min max, you can take the minimum value is equal to 13 and maximum value is equal to 70, right? so we can say the normalized value will be equal to 1335 minus 13 divided by 70 minus 13.

02:05 This is the minimum value minus 13 and the maximum values minus 30.

02:08 So that is equal to 0 .39.

02:11 So that is the normalized value.

02:13 So this is the normalized value.

02:15 Now c part, you can use z's course normalization to transform the value of 35 for age with a standard deviation is 12 .94.

02:24 So we can use you can write down mean value of age is equal to sum of all values divided by number of values.

02:32 So that is equal to you add all these things.

02:34 So you'll get total will be some value and you'll get the mean value will be equal to 32 .46.

02:40 You can do that...

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