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QUESTION 3 The truss shown in the Figure 2 below is supported by the "short link" KC and the pin (hinge) support at A. A beam is attached to the truss by cables FH and GJ. The beam carries 20 kN point load and a distributed load that varies from 4 kN/m to 0 kN/m as shown in Figure 2. Determine: a) The tension in the two cables FH and GJ supporting the beam and b) The force in each member of the truss. State whether the member is in tension, compression or a zero (0) force member. (Indicate your results on the figure provided on Page 5. and put your name and student number on this page.) 4 m K Short Link B C 6 m 4 3 m D E 6 m 3 m G A F 20 kN 4 kN/m 4 m H * 2 m 4 2 m 6 m - distributed load Figure 3(a) = \frac{1}{2} \times 6 \times 4 = 12kN/m at 6m from H 20RN J

          QUESTION 3
The truss shown in the Figure 2 below is supported by the "short link" KC and the pin (hinge)
support at A. A beam is attached to the truss by cables FH and GJ. The beam carries 20 kN point
load and a distributed load that varies from 4 kN/m to 0 kN/m as shown in Figure 2.
Determine:
a) The tension in the two cables FH and GJ supporting the beam and
b) The force in each member of the truss. State whether the member is in tension,
compression or a zero (0) force member. (Indicate your results on the figure provided
on Page 5. and put your name and student number on this page.)
4 m
K
Short Link
B
C
6 m
4
3 m
D
E
6 m
3 m
G
A
F
20 kN
4 kN/m
4 m
H
*
2 m
4
2 m
6 m
- distributed load Figure 3(a)
= \frac{1}{2} \times 6 \times 4 = 12kN/m at 6m from H 20RN
J

QUESTION 3
The truss shown in the Figure 2 below is supported by the "short link" KC and the pin (hinge)
support at A. A beam is attached to the truss by cables FH and GJ. The beam carries 20 kN point
load and a distributed load that varies from 4 kN/m to 0 kN/m as shown in Figure 2.
Determine:
a) The tension in the two cables FH and GJ supporting the beam and
b) The force in each member of the truss. State whether the member is in tension,
compression or a zero (0) force member. (Indicate your results on the figure provided
on Page 5. and put your name and student number on this page.)
4 m
K
Short Link
B
C
6 m
4
3 m
D
E
6 m
3 m
G
A
F
20 kN
4 kN/m
4 m
H
*
2 m
4
2 m
6 m
- distributed load Figure 3(a)
= (1)/(2) ×6 ×4 = 12kN/m at 6m from H 20RN
J

Added by Juan Francisco S.

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