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Question 6 1 pts The density of liquid ethanol in g/cm³ as a function of temperature T in degrees Kelvin has been correlated via the equation $\rho$ = 1.032 - 5.392$\times10^{-4}$T - 8.712$\times10^{-7}$T². The equation is dimensionally homogenous. However, we want to calculate the density in SI units i.e., kg/m³. Then the value of 1.032 in the new equation is _____. Note that 1 Btu = 1055 J, 1 ft = 0.3048 m, 1°R = (9/5) K. Hint: Use the conversion 1 g/cm³ = 1000 kg/m³ 470 1.032 516 Scanned with CS 1032 CamScanner

          Question 6
1 pts
The density of liquid ethanol in g/cm³ as a function of temperature T in degrees Kelvin has been
correlated via the equation $\rho$ = 1.032 - 5.392$\times10^{-4}$T - 8.712$\times10^{-7}$T². The equation is dimensionally
homogenous. However, we want to calculate the density in SI units i.e., kg/m³. Then the value of
1.032 in the new equation is _____. Note that 1 Btu = 1055 J, 1 ft = 0.3048 m, 1°R = (9/5) K.
Hint: Use the conversion 1 g/cm³ = 1000 kg/m³
470
1.032
516
Scanned with
CS 1032
CamScanner

Show more…

Question 6
1 pts
The density of liquid ethanol in g/cm³ as a function of temperature T in degrees Kelvin has been
correlated via the equation ρ = 1.032 - 5.392×10^-4T - 8.712×10^-7T². The equation is dimensionally
homogenous. However, we want to calculate the density in SI units i.e., kg/m³. Then the value of
1.032 in the new equation is . Note that 1 Btu = 1055 J, 1 ft = 0.3048 m, 1°R = (9/5) K.
Hint: Use the conversion 1 g/cm³ = 1000 kg/m³
470
1.032
516
Scanned with
CS 1032
CamScanner

Added by Rhonda W.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Dominador Tan

Step 1

The given equation is p = 1.032 - 5.392 × 10⁻⁴T - 8.712 × 10⁻⁷T², where p is in g/cm³ and T is in Kelvin. To convert p to kg/m³, we use the conversion factor 1 g/cm³ = 1000 kg/m³. So, the equation becomes p = (1.032 - 5.392 × 10⁻⁴T - 8.712 × 10⁻⁷T²) * 1000 kg/m³. Show more…

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The density of liquid ethanol in g/cmÂ³ as a function of temperature T in degrees Kelvin has been correlated via the equation p = 1.032 - 5.392 Ã— 10â»â´T - 8.712 Ã— 10â»â·TÂ². The equation is dimensionally homogeneous. However, we want to calculate the density in SI units, i.e., kg/mÂ³. Then the value of 1.032 in the new equation is. Note that 1 Btu = 1055 J, 1 ft = 0.3048 m, and 1 R = 9/5 K. Hint: Use the conversion 1 g/cmÂ³ = 1000 kg/mÂ³.

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