Question

Question 7 Given this circuit, if $V_{cc} = 10V$, $R_1 = 10K$, $R_2 = 20K$, $R_B = 100K$, $R_L = 470\Omega$ $\beta = 100$, what would $I_B$ be? 77.5 mA 77.5 $\mu A$ 94 mA 0 mA 94 $\mu A$

          Question 7
Given this circuit, if $V_{cc} = 10V$, $R_1 = 10K$, $R_2 = 20K$, $R_B = 100K$, $R_L = 470\Omega$
$\beta = 100$, what would $I_B$ be?
77.5 mA
77.5 $\mu A$
94 mA
0 mA
94 $\mu A$

Question 7
Given this circuit, if Vcc = 10V, R1 = 10K, R2 = 20K, RB = 100K, RL = 470Ω
β = 100, what would IB be?
77.5 mA
77.5 μ A
94 mA
0 mA
94 μ A

Added by James S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Satish Kumar

Step 1

We can use Ohm's Law to find the current flowing through Rg: Ig = Vcc / Rg Ig = 10V / 100KΩ Ig = 0.1mA Show more…

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Given this circuit, if Vcc = 10V, R = 10KÎ©, z = 20KÎ©, Rg = 100KÎ©, and RL = 470Î©, what would be +Vec? 77.5mA 77.54A 9mA

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Question

Question 7 Given this circuit, if $V_{cc} = 10V$, $R_1 = 10K$, $R_2 = 20K$, $R_B = 100K$, $R_L = 470\Omega$ $\beta = 100$, what would $I_B$ be? 77.5 mA 77.5 $\mu A$ 94 mA 0 mA 94 $\mu A$

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