Question

QUESTION 7 The differential equation y'= (4x+2y+3)$^{2}$ has solution: A. y=\sqrt{2}tan(2\sqrt{2}x+c) B. y=\frac{(4x+2y+3)^{3}}{3}+c C. y=-\frac{(4x+3)^{2}}{12}+c D. 4x+2y+3=\sqrt{2}tan(2\sqrt{2}x+c)

          QUESTION 7
The differential equation
y'= (4x+2y+3)$^{2}$
has solution:
A. y=\sqrt{2}tan(2\sqrt{2}x+c)
B. y=\frac{(4x+2y+3)^{3}}{3}+c
C. y=-\frac{(4x+3)^{2}}{12}+c
D. 4x+2y+3=\sqrt{2}tan(2\sqrt{2}x+c)

QUESTION 7
The differential equation
y'= (4x+2y+3)^2
has solution:
A. y=√(2)tan(2√(2)x+c)
B. y=((4x+2y+3)^3)/(3)+c
C. y=-((4x+3)^2)/(12)+c
D. 4x+2y+3=√(2)tan(2√(2)x+c)

Added by Catalina F.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Georgiann Andersen

Step 1

First, let's rearrange the given differential equation to isolate y on one side: y - 2y = 4x + 32 - y = 4x + 32 Show more…

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Thanks for your feedback!

The differential equation y = 4x + 2y + 32 has solution: A. y = 2tan(2x) + c B. 4x + 2y + 33 = y + 3 C. 4x + 32y = 12 D. 4x + 2y + 3 = 2tan(2x) + c

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QUESTION 7 The differential equation y'= (4x+2y+3)$^{2}$ has solution: A. y=\sqrt{2}tan(2\sqrt{2}x+c) B. y=\frac{(4x+2y+3)^{3}}{3}+c C. y=-\frac{(4x+3)^{2}}{12}+c D. 4x+2y+3=\sqrt{2}tan(2\sqrt{2}x+c)

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