Question

QUESTIONS 1. Use the bond energy values given below to calculate the enthalpy change of the reaction \[ \mathrm{N}_{2}+3 \mathrm{H}_{2} \rightarrow 2 \mathrm{NH}_{3} \] \begin{tabular}{|c|c|} \hline BONDS & BOND ENERGY \( / \mathrm{kJmol}^{-1} \) \\ \hline \( \mathrm{~N}=\mathrm{N} \) & 945 \\ \hline \( \mathrm{H}-\mathrm{H} \) & 436 \\ \( \mathrm{~N}-\mathrm{H} \) & 391 \\ \hline \end{tabular}

          QUESTIONS
1. Use the bond energy values given below to calculate the enthalpy change of the reaction
\[
\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightarrow 2 \mathrm{NH}_{3}
\]
\begin{tabular}{|c|c|}
\hline BONDS & BOND ENERGY \( / \mathrm{kJmol}^{-1} \) \\
\hline \( \mathrm{~N}=\mathrm{N} \) & 945 \\
\hline \( \mathrm{H}-\mathrm{H} \) & 436 \\
\( \mathrm{~N}-\mathrm{H} \) & 391 \\
\hline
\end{tabular}

QUESTIONS
1. Use the bond energy values given below to calculate the enthalpy change of the reaction

N2+3 H2→ 2 NH3

BONDS BOND ENERGY / kJmol^-1

N=N 945

H-H 436

N-H 391

Added by Margaret P.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Dr. Satish Ingale

Step 1

- In \( \mathrm{N}_2 \), one \( \mathrm{N} \equiv \mathrm{N} \) bond is broken. - In \( 3 \mathrm{H}_2 \), three \( \mathrm{H}-\mathrm{H} \) bonds are broken. Show more…

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QUESTIONS 1. Use the bond energy values given below to calculate the enthalpy change of the reaction \[ \mathrm{N}_{2}+3 \mathrm{H}_{2} \rightarrow 2 \mathrm{NH}_{3} \] \begin{tabular}{|c|c|} \hline BONDS & BOND ENERGY \( / \mathrm{kJmol}^{-1} \) \\ \hline \( \mathrm{~N}=\mathrm{N} \) & 945 \\ \hline \( \mathrm{H}-\mathrm{H} \) & 436 \\ \( \mathrm{~N}-\mathrm{H} \) & 391 \\ \hline \end{tabular}