00:01
Hello students, we need to write here as statistics classes estimating the mean height of all female students at their college.
00:07
They collect random sample of 36 female students and measure their point heights.
00:12
The mean of sample is 65 .3, the standard deviation is given.
00:17
We need to construct 90 % confidence interval.
00:20
So we need to write here our confidence interval would be we need to add here.
00:27
This will come out as if i write here.
00:31
Confidence interval is sample mean sample mean plus minus margin of error.
00:44
So this will come out as if i write here for this.
00:49
So this will come out as sample mean.
00:52
Sample mean is 65 .3 65 .3 plus minus t alpha y2 comma df so alpha can be written as 1 minus 0 .9 which is if i write here this is 0 .1 let's erase this to make it more clear and alpha y2 value significance level this is 0 .05 so if i write here degree of freedom is n minus 1 so n value is 36 minus 1 which is 35 so this will be let's erase this to make it more clear if i write here this is 65 .3 and this is sigma divided by under root of n so this value will come out as let's erase this to make it more clear this is plus minus so this value t alpha by 2, t of 0 .05 comma df, this is 35 multiplied by sigma.
02:00
Sigma value is 5 .2 divided by unrout of 36...