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Question 22 A gasoline engine produces 20 hp using 33 kW of heat transfer from burning fuel. The burning fuel produced originally 35 kW but there was some friction losses. 1-The thermal efficiency 2-The rejected energy per time is

          Question 22
A gasoline engine produces 20 hp using 33 kW of heat transfer from burning fuel. The burning fuel produced originally 35 kW but there was some friction losses.
1-The thermal efficiency
2-The rejected energy per time is

Question 22
A gasoline engine produces 20 hp using 33 kW of heat transfer from burning fuel. The burning fuel produced originally 35 kW but there was some friction losses.
1-The thermal efficiency
2-The rejected energy per time is

Added by David M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Kritika Mishra

Step 1

97 kW 2- The rejected energy per time is the difference between the heat input and the useful work output. We are given that the heat input is 35 kW, so we can write: Rejected energy per time = Heat input - Useful work output Rejected energy per time = 35 - Show more…

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A gasoline engine produces 20 hp using 33 kW of heat transfer from burning fuel. The burning fuel originally produced 35 kW, but there were some friction losses. 1- The thermal efficiency is 9%. 2- The rejected energy per time is # kW.