00:01
Hello friends, we have to consider the signal x of n which is equal to del n plus del n minus s.
00:06
We have del n which implies roc.
00:08
Enter z -plane and consider the time shifting property of z transformation x of n minus n naught which implies z power minus n naught into x of z.
00:17
From time shifting property del n minus 5 which implies z power minus 5.
00:21
From above we can see that poles at origin that is z equal to 0 the z -transformation will be infinite becomes 1 by 0 which is infinite.
00:30
So the roc will be entire z -plane except z equal to 0.
00:35
Thus the z -transformation of x of n which is x of z which is zt del n plus del n minus 5 which is x of z which equal to 1 plus z to the power minus 5.
00:47
Therefore the roc is the entire z -plane except z equal to 0.
00:52
We completed the first part.
00:55
We move to the second part that is consider the signal of x of n where x of n equal to minus 0 .5 to the power n u of n minus 1.
01:03
We have a power n therefore a power n u of minus n minus 1 which implies z power z minus a.
01:09
Here mod z greater than mod a...