00:01
Hello students, the memory unit has a capacity of 8192 words of 32 bits per second, bits per word.
00:11
How many flip flops are needed? so number of flip flops for the memory buffer register and memory address register, right? the two things are there.
00:23
So we need to consider the capacity of the memory unit.
00:26
The capacity is equal to 8192, this is the capacity and this is bits per word.
00:31
The two things we have.
00:32
Now, for the mar, memory address register, number of bits in mar will be equal to log of 2 log 2 of c.
00:53
So that is equal to 13 bits.
00:58
For mbr, number of flip flops for mbr will be equal to, the mbr is used to store data word being read from the written or saved from the memory unit.
01:18
So the number of bits in the mbr will be equal to the number of bits per word.
01:23
So that is in this case it is given as 32.
01:25
So that is equal to 32 flip flops.
01:30
So this is a number of mbr and this is a number of ar and br.
01:38
Okay, so this is what you require.
01:41
That's the first question...