Random samples of size $n=75$ were selected from a binomial population with $p=.4 .$ Use the normal distribution to approximate the probabilities given in Exercises 9-12. $$P(\hat{p} \leq .43)$$
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Step 1
Mean: $\mu = np = 75 \times 0.4 = 30$ Standard deviation: $\sigma = \sqrt{np(1-p)} = \sqrt{75 \times 0.4 \times 0.6} = \sqrt{18} = 3\sqrt{2}$ Show more…
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