00:01
Okay, so we have to determine here the reactivity order for the given alkyl halides.
00:04
So, here we have to keep in mind that for e2 reaction, the mole substituted is the mole reactive.
00:33
Reactive okay so now we can say that that is order of reactivity for e2 so that is 3 degree 2 degree and 1 degree that is 3 degree is the most reactive 3 degree having 3 degree tertiary alkyl halide okay that is most reactive secondary alkyl halide is less reactive and primary alkyl halide that is the least reactive one okay so now let me draw the structure first of all we have a part so this is ch3 cold wise cbr ch2 ch2 ch3 okay then we have given ch3 fold twice ch ch2 then ch2 ch2 br okay and then then ch3 fold twice ch ch2 let me draw this structure again ok there is lack of space so this is ch3 fold twice ch ch2 ch br ch3 ok now for better understanding this can also be drawn like ch3 attached to carbon containing two methyl group and br is also there right then we have ch2 ch2 ch3 okay then we have carbon with one hydrogen atom methyl group two methyl groups are there then ch2 ch2 ch3 2 br okay then for the third one we can draw the structure ch carbon with one hydrogen atom containing two methyl groups and then ch2 ch br ch3 okay now so consider this carbon this carbon containing br that consists of three alkyl group attached okay so that's why this is three degree right this carbon containing this carbon this carbon containing br group consists of two hydrogen atom and one alkyl group so that's why this is one degree and this carbon containing alkyl group attached as two alkyl groups.
05:00
So, this is two degree, okay.
05:02
So, as i told you, if i consider first position for this one, second position for this one and third position for this one, okay or let me consider a, b, c, okay.
05:19
So, that you can not be confused here in this case, okay.
05:30
So, now suppose suppose this is a, b and c.
05:36
So as i told you now b is the least reactive then c is more reactive than b and a is the most reactive...