00:01
Okay, so we have the following substrates.
00:03
We have methyl chloride, we have tert -butyl iodide, we have neopentyl bromide, we have isopropyl bromide, we have methyl iodide and ethyl chloride.
00:28
And we need to talk about the reactivity of these with respect to an sn2 reaction with sodium ethoxide.
00:43
So most important will be whether the substrate is zeroth order, primary, secondary, or tertiary.
00:52
Then we will care about leaving group in the order of iodine, bromine, chlorine, going in decreasing reactivity.
01:00
And then we will look at neighboring carbons and whether that neighboring carbon is primary, secondary, or tertiary.
01:15
Okay, so first we can begin with our zero -with order carbons.
01:18
That's methyl chloride and methyl iodide.
01:22
These are both zero -with order.
01:24
They have no substituents aside from the leaving group in hydrogen.
01:32
Right? and we know iodine is a better leaving group than chlorine...