00:01
Okay, so in this problem, we'll have to calculate the angles for each of these options.
00:06
For a slit width, d is equal to 1 over n.
00:10
So for 1 over 1 ,000 lines per centimeter, we have a slit width of 10 to the negative 5 meters.
00:17
So for the first one, a, we have d sine theta is equal to m lambda, or having lambda is 550 nanometers.
00:25
So theta is inverse sign of 550 nanometers divided by 10 to the 5 .10 to the negative.
00:30
To fifth meters, theta is 3 .15 degrees.
00:34
For part b, it's a similar thing.
00:36
Now we just changed d equals 1 over 500.
00:40
So for part b, we have a theta of 1 .6 degrees.
00:44
For part c, now we have a single slit with width of 0 .01 meters...