m = 80 kg 80°
Added by Alexandra L.
Close
Step 1
In this case, we have a person rappelling down a hill inclined at 80°. The person has a mass of 80 kg and is held by a rope. We need to find the tension in the rope. Show more…
Show all steps
Your feedback will help us improve your experience
Suzanne W. and 95 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 70 kg tightrope walker stands at the center of a rope. The rope supports are $10 \mathrm{m}$ apart and the rope sags $10^{\circ}$ at each end. The tightrope walker crouches down, then leaps straight up with an acceleration of $8.0 \mathrm{m} / \mathrm{s}^{2}$ to catch a passing trapeze. What is the tension in the rope as he jumps?
Timothy J.
Holding on to a towrope moving parallel to a frictionless ski slope, a $50 \mathrm{~kg}$ skier is pulled up the slope, which is at an angle of $8.0^{\circ}$ with the horizontal. What is the magnitude $F_{\text {rope }}$ of the force on the skier from the rope when (a) the magnitude $v$ of the skier's velocity is constant at $2.0 \mathrm{~m} / \mathrm{s}$ and $(\mathrm{b}) v=2.0 \mathrm{~m} / \mathrm{s}$ as $v$ increases at a rate of $0.10 \mathrm{~m} / \mathrm{s}^{2} ?$
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD