Question

Rate data have been determined at a particular temperature for the overall reaction in which all reactants and products are gases. 2NO + 2H2 ? N2 + 2H2O Trial Run Initial [NO] Initial [H2] Initial Rate (M·s-1) 1 0.10 M 0.20 0.0150 2 0.10 M 0.30 M 0.0225 3 0.20 M 0.20 M 0.0600 The value of the specific rate constant at this temperature is ________. ? 3.0 x 10-3 M-2·s-1 ? 0.75 M-1·s-1 ? 7.5 M-2·s-1 ? 375 M-2·s-1 ? 3.0 x 10-4 M-1·s-1

          Rate data have been determined at a particular temperature for the overall reaction in which all
reactants and products are gases.
2NO + 2H2 ? N2 + 2H2O
Trial Run Initial [NO] Initial [H2] Initial Rate (M·s-1)
1 0.10 M 0.20 0.0150
2 0.10 M 0.30 M 0.0225
3 0.20 M 0.20 M 0.0600
The value of the specific rate constant at this temperature is ________.
? 3.0 x 10-3 M-2·s-1
? 0.75 M-1·s-1
? 7.5 M-2·s-1
? 375 M-2·s-1
? 3.0 x 10-4 M-1·s-1

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Rate data have been determined at a particular temperature for the overall reaction in which all
reactants and products are gases.
2NO + 2H2 ? N2 + 2H2O
Trial Run Initial [NO] Initial [H2] Initial Rate (M·s-1)
1 0.10 M 0.20 0.0150
2 0.10 M 0.30 M 0.0225
3 0.20 M 0.20 M 0.0600
The value of the specific rate constant at this temperature is .
? 3.0 x 10-3 M-2·s-1
? 0.75 M-1·s-1
? 7.5 M-2·s-1
? 375 M-2·s-1
? 3.0 x 10-4 M-1·s-1

Added by Antonio K.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

10/07/2023

Step 1

We can do this by comparing the initial rates and concentrations from the given data. Let the rate law be: Rate = k[NO][H2]^n From Trial 1: 0.0150 = k(0.10)[(0.20)]^n From Trial 2: 0.0225 = k(0.10)[(0.30)]^n From Trial 3: 0.0600 = k(0.20)[(0.20)]^n Now, we can Show more…

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Rate data have been determined at a particular temperature for the overall reaction in which all reactants and products are gases. 2NO + 2H2 -> N2 + 2H2O Trial Run Initial [NO] Initial [H2] Initial Rate (M·s^-1) 1 0.10 M 0.20 0.0150 2 0.10 M 0.30 M 0.0225 3 0.20 M 0.20 M 0.0600 The value of the specific rate constant at this temperature is ________.

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