00:01
Hello students, according to the given question we have to calculate euclidean distances between each location with the help of the following formula.
00:13
So the formula is tab is equal to xa minus xb whole square plus y a minus y b minus y b whole square plus y a minus y b whole square.
00:32
Whole power 1 by 2.
00:36
By substituting we get 100 minus 400 whole square plus 200 minus 100 whole square whole power 1 by 2 which is equal to 90 ,000 plus 10 ,000 whole power 1 by 2.
01:06
Which is equal to 316 .23.
01:12
Now the distance for vc, that is d, d, dc is equal to xc minus xc whole square plus yb minus yc whole power 1 by 2.
01:35
By substituting we get 400 minus 100 whole square plus 100 minus 100 whole power 1 by 2.
01:53
We get 300.
01:57
For the distance, ca is equal to the formula xc minus xa whole square whole square whole power 1 by 2.
02:08
Plus yc minus ya whole square whole power 1 by 2.
02:15
By substituting we get 100 minus 100 whole square plus 100 minus 200 whole square whole power 1 by 2 which is equal to 100 so the euclidean distances are ab is equal to 316 .23 and bc is equal to 300 and for ca is equal to 100.
02:53
Here the total travel distance is equal to euclidean distance.
03:11
So deliveries per day of the destination point from a to b, is equal to 316 .23 into 4 which is equal to 1264 .92.
03:32
So the table will look like this.
03:35
So by observing all the totals, that is for the a total b and c, the location a yields the smallest total travel distance, that is in option a location a yields the smallest total travel that is 1564 .92 miles...