Question

Recall from a previous problem that the pmf of a Binomial distribution Binom (n, p) with known n can be written as f_p(y) = (n choose y) e^{y(ln(p) - ln(1-p)) + n ln(1-p)}. Rewrite f_p(y) as the pmf of a canonical exponential family: f_ heta(y) = expleft(frac{y heta - b( heta)}{phi} + c(y, phi) ight). Enter the canonical parameter heta, in terms of p, the dispersion parameter phi, and the function b( heta) below. heta = b( heta) = phi =

          Recall from a previous problem that the pmf of a Binomial distribution Binom (n, p) with known n can be written as
f_p(y) = (n choose y) e^{y(ln(p) - ln(1-p)) + n ln(1-p)}.
Rewrite f_p(y) as the pmf of a canonical exponential family:
f_	heta(y) = expleft(frac{y	heta - b(	heta)}{phi} + c(y, phi)
ight).
Enter the canonical parameter 	heta, in terms of p, the dispersion parameter phi, and the function b(	heta) below.
	heta =
b(	heta) =
phi =

$Recall from a previous problem that the pmf of a Binomial distribution Binom (n, p) with known n can be written as fp(y) = (n choose y) e^y(ln(p) - ln(1-p)) + n ln(1-p). Rewrite fp(y) as the pmf of a canonical exponential family: f heta(y) = expleft(fracy heta - b( heta)phi + c(y, phi) ight). Enter the canonical parameter heta, in terms of p, the dispersion parameter phi, and the function b( heta) below. heta = b( heta) = phi =$

Added by Maurice L.

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