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Hello guys in this problem we cover the concept of diffraction through a single slit.
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In this problem we have the wave length of the light is 633 nanometers and the width of the slit is 0 .35 meter.
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The screen is placed at a distance of 3 meter from the slit.
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Now for the first part where we have to find out the width of the central maxima.
00:34
Now, we know that in diffraction through a single thread, we defined the angular position of m -th order minima as the width of the slit a times sine theta of the m -th order equals m -times the wave -length lambda.
01:08
Now, for small angle or in case of the strict, the string, width a very, very greater than the wavelength, we can write sine theta is roughly equivalent to tan theta.
01:30
Now, on the screen, the distance from the center line consider is y.
01:37
Then we can write tan theta equals y over l...