Reduce the ratio $\frac{x^{2}-7 x+12}{x^{2}-16}$ to lowest terms.
Added by Harry H.
Step 1
Step 1: Factor the numerator and denominator of the ratio: $x^{2}-7x+12 = (x-3)(x-4)$ $x^{2}-16 = (x+4)(x-4)$ Show more…
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