00:01
Hello students, we need to find out the stoichiometric coefficient for oxygen for this reaction.
00:08
First we will write the number of carbon, hydrogen and oxygen on reactant and product side.
00:16
So on reactant side there are 4 carbon, 8 hydrogen and 3 oxygen and on product side there are 1 carbon, 2 hydrogen and 3 oxygen.
00:31
Now if we multiply this by 2, so carbon will be 2 multiplied by 4 which is 8 and hydrogen will be 2 multiplied by 8 which is 16.
00:48
Now to balance this we need to multiply it by 8 here in co2 to balance the carbon.
01:00
So there are 8 carbon in product side.
01:04
Now in case of hydrogen, there are 16 hydrogen on reactant side.
01:09
So we need to multiply water by 8.
01:13
So there will be 8 multiplied by 2, 16 hydrogen...