00:01
In this question, an ideal refrigeration cycle with r138 as a working fuel is given.
00:24
Here we will have to draw the ts diagrams with respect to the saturation lines.
00:49
Here firstly we will have to find out the three states one two three and fourth one these states then the input power and output power and the co so here the t's diagram is the the 4 state is given as this is 1, 2, 3 and here is 4.
02:25
The value can be driven as from here to here and this.
02:34
The q4 is applicable to here and q1 is applicable to here.
02:50
Here the value of w net is applied.
02:53
Now, the states here can be given by as here t4 is equal to t1 is equal to minus 16 degrees celsius.
03:12
Now, state 1.
03:17
In state 1, the values are t1 is equals to minus 16 degrees celsius, x1 is equals to 1, and for this we will have h1 is equal to 287 .74 kilojow per kjee g.
03:43
S1 is equal to 0 .9287 .9 .9 .85 kilo jiao per kajl.
03:59
Here, first, state, second.
04:06
We have p2 is equal to 1 .2m pascal is equal to 1200kcal s1 is equal to 0 .9235 kilojou per kjkk and for this h2 is equal to 2 293 .2 kilojou per kg and the value of temperature is equals to 65 degrees celsius.
05:12
First date 3, p3 is equals to 1 .2m pascal, x3 is equal to 0, h3 is equal to 0, h3 is to 118 .3157 and here the value of s3 is 0 .4 to 4 to 4 .3 kilo per kjerkal.
06:02
And at state 4 is 4 is equal to t1 is equal to to minus 16 degrees celsius.
06:18
These are the four stages...