00:01
Hello students, to change the value in the resistor a from its initial binary value that is as the 1 1 0 1 1 0 0 1 to the desired values as the 0 1 1 0 1 1 0 1 and with the 1 1 1 1 1 0 1.
00:21
So as you need to perform the logic micro operation using the resistor b as an operand.
00:27
So with the first one to change a to the 0 1 1 0 1 1 0 1.
00:37
So first is to determine the b operand.
00:40
Determine the b operand.
00:49
So the b operand should be the binary value that when combined with the a using an appropriate logical operation, the result is desired with the 0 1 1 with the 0 1 1 0 1 1 0.
01:07
So whereas a is equal to the whereas the a is equal to the whereas the a is equal to the 1 1 0 1 1 0 0 1 and the desired value as the desired value is the 0 1 1 0 1 1 0 1.
01:27
So to get from a to the desired value so as to with the big parts of the xor operation.
01:33
So b operand is equal to the a xor of the desired value of the desired value.
01:46
So whereas the b operand where a value is 1 1 0 1 1 0 0 1 with the xor of 0 1 1 0 1 1 0 1.
01:57
So to calculate after calculating this so we will be having the b operand value as 1 0 1 1 0 1 0 0.
02:08
So the next is of this logic micro operation.
02:16
So logic micro operation so here change a to the 0 1 1 0 1 1 for perform the xor between the a and b operand.
02:30
So a is equal to the a xor of b.
02:36
So with that we have the value of a that is 0 that is 1 1 0 1 1 0 0 1 with the xor value of b we have is 1 0 1 1 0 1 1 0 0.
02:50
So now after this we will be getting the value of a is equal to the is equal to the 0 1 1 0 1 1 0 1.
03:02
So this is how the a change to b is performed...