Relative velocity of S and S': The "moving" frame of reference, S', moves with an unknown velocity v as observed in the “laboratory" frame S. An event is observed in S to occur at position x = 6 × 108 m. The same event appears to an observer in S' to occur at x' = 6 × 10³ m at time t' = 4s. What is the relative velocity of the systems?
Added by Mohd E.
Step 1
Step 1: Use the Lorentz transformation equation \( x = \gamma (x' + vt') \) where \( x = 6 \times 10^8 \) m, \( x' = 6 \times 10^3 \) m, \( t' = 4 \) s, and \( \gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} \). Show more…
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