00:01
Hello everyone, during this question, have four points, one, two, three, and four.
00:05
In the first three points, we need to find out the potential energy, the kinetic energy, the mechanical energy, and the velocity, v.
00:16
For the fourth point, we were given the velocity 6 meter per second, and we need to find out the height, which is given as h.
00:24
Now potential energy is given by the mass of the object m multiplied by acceleration to gravity g multiplied by the height at which the object is kept.
00:36
The kinetic energy of an object is equal to half multiplied by its mass multiplied by square of its velocity at that point.
00:47
Mechanical energy is the summation of potential energy and kinetic energy.
00:52
You now consider point one at this point the potential energy is equal to m g multiplied by the height is equal to four meter so this is equal to the mass is given as 50 kg multiplied by g is 9 .8 meter per second square multiplied by 4 so this comes out to be equal to 1 ,960 jule the kinetic energy is equal to half multiplied by the mass m multiplied by the velocity at 1 is 0 so so have zero square the kinetic energy comes out to be equal to zero now for the mechanical energy the mechanical energy is equal to potential energy which is 1 ,960 jule plus kinetic energy is 0 so this is equal to 1 ,060 and the velocity is equal to 0 we have found out the potential energy the kinetic energy mechanical energy and the velocity at point 1 for point 2 the potential energy will be equal to the mass m multiplied by g multiplied by the height is 3 meter this is equal to 50 multiplied by 9 .8 multiplied by 3 it comes out to be equal to 1 ,470 jule to find out the kinetic energy or the velocity we'll have to apply the concept of energy conservation according to which the initial energy is equal to the final energy we'll apply energy conservation between the points 1 and so this makes one as our initial point and two as our final point we can apply energy conservation because there is no external force involved so initially we have a potential energy which is equal to 1 ,960 jule plus initially there is no kinetic energy zero equal to finally the potential energy is 1 ,470 jule plus the final kinetic energy at point two the kinetic energy at the kinetic energy at the point two comes up to be equal to 490 jude now we know that kinetic energy is given by half multiplied by the mass multiplied by square of the velocity we take the velocity to be v2 at point 2 so this is equal to 490 jude so we have here v2 square is equal to 490 multiplied by 2 multiplied by 1 divided by the mass which is 50 kg this comes out to be equal to 19 .6 taking square root on both the sides we'll find out the velocity at point 2 is equal to 4 .43 meter per second also so mechanical energy at point 2 is equal to the potential energy which is 1 ,470 jule plus the kinetic energy which is 490 this is equal to 1 ,960 joule which is same as before so for point 2 we have found out the potential energy the kinetic energy the velocity and the mechanical energy now for the next point at point 3, the potential energy will be equal to the mass am multiplied by acceleration due to gravity g multiplied by the height is 0.
04:05
So the potential energy comes up to equal to 0...