00:01
Hello students, for 1060 hotrolled steel we have sut equal to 660 megapascal and syt equal to 370 megapascal.
00:17
It is given that shaft bearing reaction forces r1 and r2, then r2 of 200 minus 13 into 150, which is is equal to 0 then r2 equal to 9 .75 kiloton we have r1 plus r2 which is equal to 30 then r1 equal to 30 minus r2 which is equal to 3 .25 kilooton the maximum bending moment acts at point of b is that is m max equal to 9.
01:01
0 .75 into 50 which is equal to 487 .5 kilo -ton millimeter.
01:11
Then sigma equal to m max into y divided by i, which is equal to 32m divided by i, which is equal to 32 into 487 .5 into 10 cube divided by 5 .25 whole cube, which is equal to 317 .8 megapascal.
01:41
Now we have endurance limit se -deh -e -dash equal to 0 .5 into s -ut, which is equal to 0 .5 -660, which is equal to 330 -magapascal.
02:00
Then ka can be written as ka equal to a into s ut or r as b, which is equal to 3 .04 into 660 rise to minus 0 .217, which is equal to 0 .7532...