Required information A 250-mH inductor is connected in parallel with a 2-k resistor. The current through the inductor is 50e-400t mA. Find the voltage v_g across the resistor. The voltage v_g across the resistor is e-400t V.
Added by Angela C.
Close
Step 1
Since the inductor and resistor are connected in parallel, the current through both components is the same. So, the current through the resistor is also 50e-400t mA. Show more…
Show all steps
Your feedback will help us improve your experience
Darshan Maheshwari and 88 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The voltage across a 200 mH inductor is given by v(t) = 3t2 + 2t +4 V for t > 0. Determine the current i(t) through the inductor. Assume that i(0) = 1A
Adi S.
The voltage across a $15.0-\mathrm{H}$ inductor is given by $v=28.5+\sqrt{6 t} \mathrm{V} .$ Find the current in the inductor at $2.50 \mathrm{s}$ if the initial current is $15.0 \mathrm{A}.$
The current through a 40 -mH inductor is $$i(t)=\left\{\begin{array}{ll} 0, & t<0 \\ t e^{-2 t} \mathrm{A}, & t>0 \end{array}\right.$$ Find the voltage $v(t)$
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD