Question

Required information In the circuit shown, $R_1 = 12.9 \Omega$, $R_2 = R_4 = 40.0 \Omega$, $R_3 = 20.0 \Omega$, $R_5 = 12.9 \Omega$, and voltage $V = 23.6 V$. What is the power dissipated by $R_3$?

          Required information
In the circuit shown, $R_1 = 12.9 \Omega$, $R_2 = R_4 = 40.0 \Omega$, $R_3 = 20.0 \Omega$, $R_5 = 12.9 \Omega$, and voltage $V = 23.6 V$.
What is the power dissipated by $R_3$?

Required information
In the circuit shown, R1 = 12.9 Ω, R2 = R4 = 40.0 Ω, R3 = 20.0 Ω, R5 = 12.9 Ω, and voltage V = 23.6 V.
What is the power dissipated by R3?

Added by Marie L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Nishant Kumar

09/20/2022

Step 1

The resistors R2 and R5 are in parallel, so their equivalent resistance is: $$R_{25} = \frac{R_2 \cdot R_5}{R_2 + R_5} = \frac{40.0 \Omega \cdot 12.9 \Omega}{40.0 \Omega + 12.9 \Omega} = 9.6 \Omega$$ Show more…

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Required information In the circuit shown, R₁ = 12.9 Ω, R2 = R4 = 40.0 Ω, R3 = 20.0 Ω, R5 = 12.9 Ω, and voltage V = 23.6 V. V R1 R3 R2 R5 R4 What is the power dissipated by R3? W