Question

Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A wind turbine is rotating at 15 rpm under steady winds flowing through the turbine at a rate of 43400 kg/s. The tip velocity of the turbine blade is measured to be 250 km/h. Assume 180 kW power is produced by the turbine and answer the questions that follow. Take the density of air to be 1.31 kg/m^3. Determine the average velocity of the air. (You must provide an answer before moving to the next part.) The average velocity of the air is [ ] m/s.

          Required information
NOTE: This is a multi-part question. Once an answer is
submitted, you will be unable to return to this part.
A wind turbine is rotating at 15 rpm under steady winds flowing
through the turbine at a rate of 43400 kg/s. The tip velocity of
the turbine blade is measured to be 250 km/h. Assume 180 kW
power is produced by the turbine and answer the questions
that follow.
Take the density of air to be 1.31 kg/m^3.
Determine the average velocity of the air.
(You must provide an answer before moving to the next part.)
The average velocity of the air is [ ] m/s.
        
Show more…
Required information
NOTE: This is a multi-part question. Once an answer is
submitted, you will be unable to return to this part.
A wind turbine is rotating at 15 rpm under steady winds flowing
through the turbine at a rate of 43400 kg/s. The tip velocity of
the turbine blade is measured to be 250 km/h. Assume 180 kW
power is produced by the turbine and answer the questions
that follow.
Take the density of air to be 1.31 kg/m^3.
Determine the average velocity of the air.
(You must provide an answer before moving to the next part.)
The average velocity of the air is [ ] m/s.

Added by Brian A.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Transcript

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00:01 Determine the average velocity of the air.
00:03 So we're given omega.
00:04 Now our velocity at our tip is given as 250 kilometers per hour or 69 .4 meters per second now the velocity can be rewritten as pi omega d divided by 60 so we can set 69 .4 equal to pi d times 15 divided by 60 and solve for d.
00:26 D is then 88 .4 meters and so then our radius is 44 .2 meters.
00:34 We just divide that by two...
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