00:05
In this question, we first need to find the simple linear regression model.
00:10
So the equation for simple linear regression model, for simple linear regression model, the equation is y is equals to a plus x.
00:35
Now where y is the temperature, x is the coded year and a and b are the coefficient we needed.
00:42
So now next we need to fit a third order polynomial regression model.
00:50
So the equation, the equation for third order polynomial, third order polynomial regression model, that is we have y is equals to a plus bx plus cx square plus bx cube where y is the temperature, x is the year, coded year and a, b, c are the coefficient.
01:44
We needed to find now to determine which model fits the data better, we can compare r square values on both.
01:51
So what we will do, we will compare r square value of both model.
02:10
So higher the r square value, the better is the model fits.
02:14
So we can use the better fitting model to predict the global mean temperature for year what? for year 1960.
02:28
So we can calculate the coefficient for both the model to find the following equation.
02:34
So simple linear regression model equation is what? so y is equals to 13 .5 plus we have 0 .1x.
02:46
So the third order polynomial regression, this is the linear one and the third order, the third order equation is y is equals to 13 .4 plus we have 0 .15x plus we have, this is negative value so this will become minus 0 .01x square plus we have 0 .0002x cube...