00:01
In this question, let's start with the first circuit.
00:04
So for the circuit a, for circuit a from the law of oms, that is v, which is equals to ir, we can find out the current.
00:17
Here we have the value of a v, that is 9 watt, which is equals to i multiplied by r, that is 3 om.
00:26
So it becomes a current i, which is equal to 3 .m.
00:31
So this is the current passing through the bulb that is 3 ampere.
00:39
Now in the circuit b in the circuit b similarly here we have two resistors of 3 o each are connected in parallel therefore let's first write down the equivalent resistor as 3 multiplied by 3 divided by 3 plus 3.
01:03
So it becomes around 1 .5 own.
01:07
And now using again same oms law, we can find out the value of a current i, which is equals to v, that is 9, divided by equivalent resistor...