Question

4. A 5.00 kg object, object A, moving at 5.50 m/s to the right collides head on with a 3.50 kg object, object B, that is a rest. The 5.00 kg object ends up with a speed of 1.50 m/s in the opposite direction. (a) What is the velocity of object B after the collision? (b) How much kinetic energy is transferred to object B during the collision? Before Diagram After Diagram Solution 5.00 m/s 0 m/s 1.50 m/s ?Pi = ?Pf A B A B 5.00 kg 3.50 kg 5.00 kg 3.50 kg V = KE = 5. A 0.015 kg toy car moving at 0.2 m/s has a collision with a 0.02 kg toy car moving in the opposite direction at 0.3 m/s. After the collision, the 0.015 kg car moves backwards with a velocity of 0.37 m/s. a. Find the velocity of the 0.02 kg car after the collision. b. Verify your answer by calculating the total kinetic energy before and after the collision. Before Diagram After Diagram Solution ?Pi = ?Pf V = KEi = KEf =

          4. A 5.00 kg object, object A, moving at 5.50 m/s to the right collides head on with a 3.50 kg object, object B, that is a rest. The 5.00 kg object ends up with a speed of 1.50 m/s in the opposite direction.
(a) What is the velocity of object B after the collision?
(b) How much kinetic energy is transferred to object B during the collision?
Before Diagram
After Diagram
Solution
5.00 m/s 0 m/s
1.50 m/s
?Pi = ?Pf
A B
A B
5.00 kg 3.50 kg
5.00 kg 3.50 kg
V =
KE =
5. A 0.015 kg toy car moving at 0.2 m/s has a collision with a 0.02 kg toy car moving in the opposite direction at 0.3 m/s. After the collision, the 0.015 kg car moves backwards with a velocity of 0.37 m/s.
a. Find the velocity of the 0.02 kg car after the collision.
b. Verify your answer by calculating the total kinetic energy before and after the collision.
Before Diagram
After Diagram
Solution
?Pi = ?Pf
V =
KEi =
KEf =

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4. A 5.00 kg object, object A, moving at 5.50 m/s to the right collides head on with a 3.50 kg object, object B, that is a rest. The 5.00 kg object ends up with a speed of 1.50 m/s in the opposite direction.
(a) What is the velocity of object B after the collision?
(b) How much kinetic energy is transferred to object B during the collision?
Before Diagram
After Diagram
Solution
5.00 m/s 0 m/s
1.50 m/s
?Pi = ?Pf
A B
A B
5.00 kg 3.50 kg
5.00 kg 3.50 kg
V =
KE =
5. A 0.015 kg toy car moving at 0.2 m/s has a collision with a 0.02 kg toy car moving in the opposite direction at 0.3 m/s. After the collision, the 0.015 kg car moves backwards with a velocity of 0.37 m/s.
a. Find the velocity of the 0.02 kg car after the collision.
b. Verify your answer by calculating the total kinetic energy before and after the collision.
Before Diagram
After Diagram
Solution
?Pi = ?Pf
V =
KEi =
KEf =

Added by Zoe Q.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

04/20/2023

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Find the velocity of the 0.02 kg car after the collision. Show more…

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Rest. The 5.00 kg object ends up with a speed of 1.50 m/s in the opposite direction. (a) What is the velocity of object B after the collision? (b) How much kinetic energy is transferred to object B during the collision? Before Diagram: After Diagram: Solution: KE = 5. A 0.015 kg toy car moving at 0.2 m/s has a collision with a 0.02 kg toy car moving in the opposite direction at 0.3 m/s. After the collision, the 0.015 kg car moves backwards with a velocity of 0.37 m/s. a. Find the velocity of the 0.02 kg car after the collision. b. Verify your answer by calculating the total kinetic energy before and after the collision. Before Diagram: After Diagram: Solution: V = KEi = KEf =

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Transcript

00:02 Hello here let's first solve question four.

00:05 In question four object a has a mass of five kilograms and it's moving at a speed of five and a half meters per second to the right.

00:20 It collides with an object m2, mass of three and a half kilograms and after the collision a has a speed of 1 .50 meters per second in the opposite direction.

00:42 In question a we have to find velocity of b after the collision.

00:49 Let's do this.

00:50 Let's make a quick sketch so that's before the collision and after the collision a bounces back, b moves to the right.

01:11 It means that ma va initial is negative ma va final plus mb vb final.

02:13 That is 10 meters per second and now we have to find how much kinetic energy is transferred to b during the collision.

02:25 This kinetic energy is mass of the block b times its squared speed over two.

02:32 That's 175 joules.

02:47 Now let's move on to question two.

02:50 Question five.

02:53 In question five car has a mass of 0 .015 kilograms.

03:03 Let's call it m1 and its initial speed is 0 .2 meters per second.

03:12 It collides with a second car of mass of 0 .02 kilograms moving in the opposite direction at v2 initial which is 0 .3 meters per second.

03:29 After the collision m1 moves backwards with 0 .3 meters per second with 0 .37 meters per second.

03:49 Here we have to find velocity of the second car after the collision.

04:00 So that's directed along v1 initial and therefore here let's basically make a quick sketch...

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