Restate the percent yields and distribution of products for...

Restate the percent yields and distribution of products for each reaction. Is one reaction more selective than the other? Why? Consider the mechanisms of the reactions. $X_1 \rightleftharpoons X^2$ The percents yields were 3.37 and 1.61. The first reaction was more selective than the other because the percent yield was much higher in the first one than the second one.

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00:01 Welcome here in this question we have a reaction a is giving rise to a plus b is giving rise to 2c and a plus 2b giving rise to d so here a and b are giving and here a is present in the product side 1 .5 mass percent and b is given 32 .58 mass percent is there and c is 45 .25 mass percent and d is 12 14 .02 mass percent is given and molar mass of this one is given as 24 per a and 18 for b and 42 for c and 60 for d so we have to find out the total moles of calculate the percent conversion of a b and yield of c the select and the percent excess of be given in the information below we have to find out so here we will find out the number of moles of a present in number of moles of a present in the product side is equal to so 100 grams is a product so that there is under in the 100 grams 8 .5 is present a so 8 .5 grams divided by 20 then it is equal to here the number of moles of a is 0 .34.

01:41 And here number of moles of b is 32 .58 divided by 18.

01:48 Then it is equal to 1 .8 1 moles and c is 45 .25 divided by 42 that is 1 .08.

01:58 And d is 14 .02 divided by 60 then it is equal to 0 .3 moles now the percentage of a so that is produced from the a plus b giving rise to c the reaction here the number of moles of a number of moles of a consumed is equal to number of moles of a consumed is equal to number of moles of of b consumed is equal to number of moles of c so this is half of the number of moles of c half one by two number of moles of c half of c so here from this one here b consumed is equal to a consumed that is equal to so number of moles of b consumed is equal to 0 .18 divided by c is due 0 .2 here c is produced so then it is equal to 0 .5 4 is a amount of c a consumed and c produced so a is equal to among total moles of a a consumed is equal to so from d also we will calculate right so here from a plus a plus to b is equal to d so here amount of a consumed is equal to is equal to amount of uh d produced is equal to half of half is two multiplied by two m two times of de formed is de formed is amount of be formed be consumed so we will calculate a consumed is equal to how much it is produced 0 .3 moles, a is consumed, and how much b is consumed 2 multiplied by 0 .3.

04:21 So, 2, 3, that is equal to 0 .46 is the amount of b consumed...

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