revcaled thal the average life span was 855 hours with standar deviation of sumple of 25 bght bu

here in this question we are given a sample of 25 light bulbs this 25 light bulbs average hover

Hello students, according to the given question we have to find the test statistic value. So, he

The descriptive statistics are x far is 724 .1, S is 156 .9 and N is 15. So the null hypothesis

Okay, let's start the solution. So here let let mu denote the average life mu denote the average

According to this question, we have to find out p value of the test. So it started that H0 and m

Question

The study revealed that the average lifespan was 855 hours with a standard deviation of a sample of 25 bright bulbs. Assuming a normal distribution for the lifespan of the population of light bulbs, test the claim at 130 hours of significance that the mean lifespan of the population of light bulbs is less than 865 hours (20 pts, Î± = 0.01 level). State the claim (Zpt): The claim is that the mean lifespan of the population of light bulbs is less than 865 hours. State the Null Hypothesis (Zpt): The null hypothesis is that the mean lifespan of the population of light bulbs is equal to or greater than 865 hours. State the Alternative Hypothesis (2pl): The alternative hypothesis is that the mean lifespan of the population of light bulbs is less than 865 hours. Determine the type of test used (Jpt): The type of test used is a one-tailed test. Determine the critical value(s) (CV) (Zpt): The critical value for a one-tailed test at Î± = 0.01 level is -2.33. Find the Test statistic (TS) (8 pt): The test statistic is calculated using the formula: TS = (sample mean - hypothesized mean) / (sample standard deviation / âˆšsample size). Decision and conclusion (Spts): Compare the test statistic to the critical value. If the test statistic is less than the critical value, reject the null hypothesis. Otherwise, fail to reject the null hypothesis. Based on the decision, conclude whether there is enough evidence to support the claim.

          The study revealed that the average lifespan was 855 hours with a standard deviation of a sample of 25 bright bulbs. Assuming a normal distribution for the lifespan of the population of light bulbs, test the claim at 130 hours of significance that the mean lifespan of the population of light bulbs is less than 865 hours (20 pts, Î± = 0.01 level).

    State the claim (Zpt): The claim is that the mean lifespan of the population of light bulbs is less than 865 hours.
    State the Null Hypothesis (Zpt): The null hypothesis is that the mean lifespan of the population of light bulbs is equal to or greater than 865 hours.
    State the Alternative Hypothesis (2pl): The alternative hypothesis is that the mean lifespan of the population of light bulbs is less than 865 hours.
    Determine the type of test used (Jpt): The type of test used is a one-tailed test.
    Determine the critical value(s) (CV) (Zpt): The critical value for a one-tailed test at Î± = 0.01 level is -2.33.
    Find the Test statistic (TS) (8 pt): The test statistic is calculated using the formula: TS = (sample mean - hypothesized mean) / (sample standard deviation / âˆšsample size).
    Decision and conclusion (Spts): Compare the test statistic to the critical value. If the test statistic is less than the critical value, reject the null hypothesis. Otherwise, fail to reject the null hypothesis. Based on the decision, conclude whether there is enough evidence to support the claim.

revcaled thal the average life span was 855 hours with standar deviation of sumple of 25 bght bulba acrumin notmal distribution for the lifespan of the population of light bulbs test the cla 37692

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